Question

The sum of two positive integers is 42. When the smaller integer is subtracted from three times the larger, the result is 46. Fine the two integers.

Answer 1

Let the smaller integer be 'x'

So larger integer is (42 - x)

3(42 - x) - x = 46

126 - 3x - x = 46

80 = 4x

x = 20

So the numbers are 22 and 20

Answer 2

Answer:

x = 22 and y = 20

Step-by-step explanation:

• Let the integers be x and y respectively
• Given ,
• x + y = 42          --------  eq 1
• 3x - y = 46         --------  eq 2
• Now from eq 1 ,
• y = 42 - x
• Substituting in eq 2 we get ,
• 3x - ( 42 - x ) = 46
• 3x - 42 + x = 46
• 3x - 42 - 46 + x = 0
• 4x - 88 = 0
• 4x = 88
• x = 22
• y = 20