Question

The sum of two positive integers is 52 and their L.C.M is 168.Find the numbers. (plzz solve in a easy manner)

Answer 1

$let \: the \: hcf \: be \: h \: and \: other \: two \: number \: be \: ha \: and \: hb \\ \\ given \: sum \: of \: number \: is \: 52 \\ \: ha + hb \: = 52 \\ h(a + b) = 52 \\ lcm \: \times hcf \: = product \: of \: number \\ 168 \times h = ha \times hb \\ hab = 168 \\ by \: calculation \: get \: \\ h = 4\: a = 7 \: b = 6 \: \\ \\ so \: the \: no \: ha \: and \: hb \: are \: 4 \times 6 = 24 \: , 4 \times 7 = 28 \:$

Answer 2

Answer:

givensumofnumberis52

ha+hb=52

h(a+b)=52

lcm×hcf=productofnumber

168×h=ha×hb

hab=168

bycalculationget

h=4a=7b=6

sothenohaandhbare4×6=24,4×7=28