the sum of two positive integers is 98. the integer are in the ratio of 3: 4.Find the integers.
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You appear to have 2 different problem statements, one in the title and one in the description. I will assume the one in the title is correct, and I will work that one.
n + m = 98
n/m = 3/4
n = (3/4)m
(3/4)m + m = 98
(7/4)m = 98
m = (4/7)98 = 56
n = 98 - m = 98 - 56 = 42
Note that
n/m = 42/56 = 3/4
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