The sum of two positive numbers is 20% of the sum of the squares of both the numbers and different 25% of the two numbers. If both numbers are x and y, then x + y / x ^ 2 =
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Step-by-step explanation:
Let the ture positive numbers be x,(x,y>0)
x+y=20 - Given
We need to maximise x2y3
x=20−y
f(y)=y3(20−y)2
for minimum
f′(y)=0
3y2(20−y)2+y32(20−y)(−1)=0
3y2(20−y)2−2y3(20−y)=0
y2(20−y)(3(20−y)−2y)=0
60−3y−2y=0 y is not equal 0&y is also not equal 20
y=12 if y=20 then x=0 which does not
x=8 make the x2y3 maximum
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