The sum of two positive odd integers is 216. find the small of the two .
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Answered by
15
Let the positive odd integer be x
The next odd integer would be x+2
x+x+2=216
2x=214
107
So first odd integer is 107 and the next is 109
The next odd integer would be x+2
x+x+2=216
2x=214
107
So first odd integer is 107 and the next is 109
sonu223:
thanks
its ok sonu
Answered by
5
The next three odd integers then are x+2, x+4, and x+6.
If we add all 4 together, they should equal 216.
x + (x+2) + (x+4) + (x+6) = 216
Now group like terms and solve for x.
4x + 12 = 216
4x = 204
x = 51.
That means the four consecutive odd integers are 51, 53, 55, and 57.
Check: 51 + 53 + 55 + 57 = 216. Correct.
If we add all 4 together, they should equal 216.
x + (x+2) + (x+4) + (x+6) = 216
Now group like terms and solve for x.
4x + 12 = 216
4x = 204
x = 51.
That means the four consecutive odd integers are 51, 53, 55, and 57.
Check: 51 + 53 + 55 + 57 = 216. Correct.
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