Question

the sum of two ratioanl no. is 17/69.if one of them is 1/23 , find the other rational no.​

Answer 1

Let, the other number is x

so, 1/23 + x = 17/69

× = 17/69 - 1/23

x = 391 - 69/1587

x = 322/1587

x = 14/69

then the other number is 14/69

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The second number is $\tt{\dfrac{14}{69}}$

$\mathfrak{\large{\underline{\underline{Explanation :- }}}}$

Given :

The sum of the numbers = $\tt{\dfrac{17}{69}}$

One of the rational numbers = $\tt{\dfrac{1}{23}}$

To find :

The second number

Solution :

Consider the second number as x

$\tt{\implies} \: \dfrac{1}{23} + x = \dfrac{17}{69}$

$\tt{\implies} \: x = \dfrac{17}{69} - \dfrac{1}{23}$

LCM of 69 and 23 = 69

$\tt{\implies} \: x = \dfrac{17}{69} - \dfrac{1 \times 3}{23 \times 3}$

$\tt{\implies} \:x = \dfrac{17 - 3}{69}$

$\tt{\implies} \: x = \dfrac{14}{69}$

$\therefore$ The second number is $\tt{\dfrac{14}{69}}$

$\mathfrak{\large{\underline{\underline{Verification :- }}}}$

$\tt{\implies} \: \dfrac{1}{23} + \dfrac{14}{69} = \dfrac{17}{69}$

LCM of 23 and 69 = 69

$\tt{\implies} \: \dfrac{1 \times 3}{23 \times 3} + \dfrac{14}{69} = \dfrac{17}{69}$

$\tt{\implies} \: \dfrac{3 + 14}{69} = \dfrac{17}{69}$

$\tt{\implies} \: \dfrac{17}{69} = \dfrac{17}{69}$

$\therefore$ The second number is $\tt{\dfrac{14}{69}}$