Question

The sum of two rational number is 14 by 33 if one of the number is minus 7 by 11 find the other

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Other\:number=\frac{35}{33}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{given : }} \\ \tt{: \implies sum \:of \: two \: rational \: numbers = \frac{14}{33}} \\ \\ \tt{: \implies one \: number = \frac{ - 7}{11} } \\ \\ \red{\underline \bold{to \: find : }} \\ \tt{: \implies other \: number =?}$

• In the given question information given about the sum of two rational number that is 14/33 and first number is -7/11.

• We have to find the other number.

• According to given question :

$\text{let \: the \: other \: number \: be \: p} \\ \\ \bold{as \: we \: know \: that} \\ \tt{: \implies \frac{ - 7}{11} + p = \frac{14}{33} } \\ \\ \tt{: \implies p = \frac{14}{33} + \frac{7}{11}} \\ \\ \bold{taking \: lcm \: of \: 33 \: and \: 11}\\ \tt{: \implies p = (\frac{14}{33} \times \frac{1}{1} )+ ( \frac{7}{11} \times \frac{3}{3}) } \\ \\ \tt{: \implies p = \frac{14}{33} + \frac{21}{33} } \\ \\ \tt{: \implies p = \frac{14 + 21}{33} } \\ \\ \green{\tt{: \implies p = \frac{35}{33}}}$