Question

the sum of two rational number is -3/5 .if one number is -9/20 then what is the another number​

Answer 1

$\large\boxed{\bf{\green{\underline{\underline{❣\:GIVEN\:❣}}}}}$

$\large{\sf{\pink{Sum \:of\: two\: rational\: numbers\: is \:\frac{-3}{5}}}}$

$\large{\sf{\pink{One\: number\: is \:\frac{-9}{20}}}}$

$\large\boxed{\bf{\green{\underline{\underline{❣\:To\:Find\:❣}}}}}$

$\large{\sf{\pink{Other\: number.}}}$

$\large\boxed{\bf{\green{\underline{\underline{❣\:SOLUTION\:❣}}}}}$

It is given the sum of two rational nos.

$\large\red\longrightarrow{\sf{\red{So\:let \:the\: other\: number \:be \:x.}}}$

$\huge\blue{SO\:ATQ, }$

$\large\red\Longrightarrow{\bf{\red{x+\frac{-9}{20}=\frac{-3}{5}}}}$

$\large\red\Longrightarrow{\bf{\red{x=\frac{-3}{5}-\frac{-9}{20}}}}$

After doing the LCM of 5 and 20 we get,

$\large\red\Longrightarrow{\bf{\red{x=\frac{-12-(-9)}{20}}}}$

$\large\red\Longrightarrow{\bf{\red{x=\frac{-12+9}{20}}}}$

$\large\red\Longrightarrow{\bf{\red{x=\frac{-3}{20}}}}$

$\large\red\therefore\boxed{\bf{\red{The\:other\:number\:=\frac{-3}{20}}}}$

$\large\underline{\sf{\green{Let's\: verify\: it\::-}}}$

$\large\red\Longrightarrow{\bf{\red{\frac{-3}{20}+\frac{-9}{20}=\frac{-3}{5}}}}$

$\large\red\Longrightarrow{\bf{\red{\frac{(-3)+(-9)}{20}=\frac{-3}{5}}}}$

$\large\red\Longrightarrow{\bf{\red{\frac{-3-9}{20}=\frac{-3}{5}}}}$

$\large\red\Longrightarrow{\bf{\red{\frac{-12}{20}=\frac{-3}{5}}}}$

$\large{\sf{\red{After\: the\: cancellation \:of \frac{-12}{20} \:we\: get,}}}$

$\large\red\Longrightarrow{\bf{\red{\frac{-3}{5}=\frac{-3}{5}}}}$

$\large\red\therefore{\bf{\red{LHS=RHS}}}$

SO THE OTHER NUMBER IS $\huge\frac{-3}{20}$