Question

the sum of two rational numbers-23/9.if one of the members is 5/9.​

Answer 1

Answer:

Let the other number be x.

x + 5/9 = -23/9

x = -23/9 - 5/9

x = -28/9

Hence the other number is -28/9.

Answer 2

❍ Let's Consider second rational number be x .

Given that ,

• The sum of two rational numbers-23/9.if one of the members is 5/9.

Then ,

• $\star\sf{ Equation = \dfrac{5}{9} + x = \dfrac{-23}{9}}$

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Solving\:for\:x \:in\: the \: Formed \: Equation \::}}$

$\qquad:\implies\sf{ Equation = \dfrac{5}{9} + x = \dfrac{-23}{9}}$

$\qquad:\implies\sf{ \dfrac{5}{9} + x = \dfrac{-23}{9}}$

$\qquad:\implies\sf{ x = \dfrac{-23}{9}-\dfrac{5}{9}}$

$\qquad:\implies\sf{ x = \dfrac{-23-5}{9}}$

$\qquad:\implies\sf{ x = \dfrac{-28}{9}}$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  x = \dfrac{-28}{9}\: }}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm { Hence,\:The\:Second \:Rational \:number \:is\:\bf{\dfrac{-28}{9}\: }}}}$

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V E R I F I C A T I O N :

As, We know that ,

• $\star\sf{ Equation = \dfrac{5}{9} + x = \dfrac{-23}{9}}$

Where,

• $\qquad:\implies\sf{ x = \dfrac{-28}{9}}$

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Substituting \:\:x \:in\: the \: Formed \: Equation \::}}$

$\qquad:\implies\sf{ Equation = \dfrac{5}{9} + \dfrac{-28}{9} = \dfrac{-23}{9}}$

$\qquad:\implies\sf{ \dfrac{5}{9} + \dfrac{-28}{9} = \dfrac{-23}{9}}$

$\qquad:\implies\sf{ \dfrac{5+ (-28)}{9} = \dfrac{-23}{9}}$

$\qquad:\implies\sf{ \dfrac{5 -28}{9} = \dfrac{-23}{9}}$

$\qquad:\implies\sf{ \dfrac{-23}{9} = \dfrac{-23}{9}}$

⠀⠀⠀⠀⠀$\therefore {\underline {\bf{ Hence, \:Verified \:}}}$

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