Question

The sum of two rational numbers is -3.If 2one of the numbers is -11/6,find the other​

Answer 1

➤ Answer :-

${ \tt \longrightarrow \dfrac{( - 11)}{6} + \sf(x) \tt = - 3}$

To find the value of 'x' in the following sum we should subtract the answer and the first value...

${ \sf \longrightarrow (x) \tt = ( - 3 )- \dfrac{( - 11)}{6} }$

${\tt \longrightarrow \dfrac{( - 3)}{1} - \dfrac{( - 11)}{6} }$

Convert them into like fractions by taking the LCM of the denominators i.e, 1 and 6.

LCM of 1 and 6 is 6.

${\tt \longrightarrow \dfrac{( -3) \times 6}{1 \times 6} - \dfrac{( - 11)}{6} }$

${\tt \longrightarrow \dfrac{( - 18)}{6} - \dfrac{( - 11)}{6} = \dfrac{( - 18) - ( - 11)}{6} }$

${ \tt \longrightarrow \dfrac{( - 18) + 11}{6} = \dfrac{7}{6} }$

${ \tt \longrightarrow \dfrac{7}{6} = 1 \dfrac{1}{6} }$

$\Huge\therefore$The other number is $\tt 1 \dfrac{1}{6}$

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More to know..............

• While adding the fractions if the first value is not given, we should subtract the answer and the second value.
• While adding the fractions if the second value is not given, we should subtract the answer and the first value.
• While subtracting the fractions if first value is not given, we should add the answer and the second value.
• While subtracting the fractions if the second value is not given, we should subtract the first value and the the answer.