Math, asked by gajrajsingh07, 5 hours ago

the sum of two rational numbers is -4 if one of them is -11/5 find the other​

Answers

Answered by gauravpandey25
2

Step-by-step explanation:

the sum of two rational numbers is -4 if one of them is -11/5 find the other

Answered by BlessedOne
120

Given :

  • Sum of two rational numbers is ( -4 )

  • One of the number is \bf\:\frac{-11}{5}

To find :

  • The other number sum of which with \bf\:\frac{-11}{5} gives ( -4 )

Concept :

In this question we are said that the sum of two rational numbers is ( -4 ) . One of the number is given as \bf\:\frac{-11}{5} . We are asked to find the other rational number . So for this we would assume any variable as the other number . Then after we would form an equation following the criteria of the question . Solving the equation we would get our final answer.

Hope am clear let's solve it :D~

Assumption :

Let the other rational number be x.

Solution :

According to the question -

Sum of x and \tt\:\frac{-11}{5} = ( -4 )

\tt\implies\:x+(\frac{-11}{5})=(-4)

Multiplying the signs

\tt\implies\:x-\frac{11}{5}=(-4)

LCM of 1 and 5 = 5

\tt\implies\:\frac{(5 \times x) - ( 1 \times 11)}{5}=(-4)

\tt\implies\:\frac{5x - 11}{5}=(-4)

Cross multiplying

\tt\implies\:5x - 11=(-4) \times 5

\tt\implies\:5x - 11=(-20)

Transposing (-11) to RHS it becomes +11

\tt\implies\:5x =(-20)+11

\tt\implies\:5x =(-9)

Transposing 5 to RHS it goes to the denominator

\small{\underline{\boxed{\mathrm{\implies\:x=(\frac{-9}{5})}}}}

Verifying :

Plugging the value of x as -9/5 in the equation formed earlier -

\tt\:x+(\frac{-11}{5})=(-4)

\tt\mapsto\:\frac{-9}{5}+(\frac{-11}{5})=(-4)

\tt\mapsto\:\frac{-9}{5}-\frac{11}{5}=(-4)

LCM of 5 and 5 = 5

\tt\mapsto\:\frac{-9}{5}-\frac{11}{5}=(-4)

\tt\mapsto\:\frac{-9-11}{5}=(-4)

\tt\mapsto\:\frac{-20}{5}=(-4)

Cross multiplying

\tt\mapsto\:-20=(-4) \times 5

\tt\mapsto\:-20=-20

\bf\mapsto\:LHS=RHS

Hence Verified !~

______________________

Therefore :

⠀⠀ ⠀⠀ ⠀❒ The other rational number is \large{\mathfrak\red{(\frac{-9}{5})}}

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