Question

The sum of two rational numbers is -6. If one of them is
then find the other.​

Answer 1

Answer:

u did not give the correct question

Step-by-step explanation:

see ur question before posting it anyhow answer is -3

Answer 2

Solution:-

Method :- 1

Factorization method

\rm : \implies {x}^{2} - 4x + 3 = 0:⟹x

2

−4x+3=0

Splitting into middle term

\rm : \implies {x}^{2} - 3x - x + 3 = 0:⟹x

2

−3x−x+3=0

\rm : \implies x(x - 3) - (x - 3) = 0:⟹x(x−3)−(x−3)=0

\rm : \implies (x - 3)(x - 1) = 0:⟹(x−3)(x−1)=0

\rm : \implies x = 3 \: \: and \: \: x \: = 1:⟹x=3andx=1

Method :- 2

Quadratic formula method

\boxed{ \rm \: x = \dfrac{ - b \pm \sqrt{D} }{2a} }

x=

2a

−b±

D

given equation :-

\rm : \implies {x}^{2} - 4x + 3:⟹x

2

−4x+3

Now compare with

\rm : \implies {a}^{2} + bx + c = 0:⟹a

2

+bx+c=0

So

\rm : \implies a = 1 \: \: b \: = - 4 \: and \: c \: = 3:⟹a=1b=−4andc=3

Find the Discriminant

\rm : \implies D = {b }^{2} - 4ac:⟹D=b

2

−4ac

Now we get

\rm : \implies D = ( - 4) {}^{2} - 4 \times 3 \times 1:⟹D=(−4)

2

−4×3×1

\rm : \implies D = 16 - 12:⟹D=16−12

\rm : \implies D = 4:⟹D=4

Now use quadratic formula

\boxed{ \rm \: x = \dfrac{ - b \pm \sqrt{D} }{2a} }

x=

2a

−b±

D

\rm : \implies x = \dfrac{ - ( - 4) \pm \sqrt{4} }{2 \times 1}:⟹x=

2×1

−(−4)±

4

\rm : \implies x = \dfrac{4 \pm2}{2}:⟹x=

2

4±2

\rm : \implies x = \dfrac{4 + 2}{2} \: and \: x = \dfrac{4 - 2}{2}:⟹x=

2

4+2

andx=

2

4−2

\rm : \implies x = 3 \: \: \: and \: \: x = 1:⟹x=3andx=1