Question

the sum of two rational numbers is 73/63. if one rational number is 5/7, find the other rational number.​

Answer 1

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✠ The sum of two rational numbers is 73/63. if one rational number is 5/7, find the other rational number.

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Let the other number be x.

$\displaystyle{ \implies \: \frac{5}{7} + x = \frac{73}{63} }$

$\displaystyle{ \implies \: x = \frac{73}{63} - \frac{5}{7} }$

❖ Taking LCM as 63.

$\displaystyle{ \frac{5 \times 9}{7 \times 9} = \frac{45}{63} }$

$\displaystyle{ \implies \: x = \frac{73 - 45}{63} }$

$\displaystyle{ \implies \: x = \frac{28}{63} }$

∴ The other fraction is 28/63.

$\red{\mid{\fbox{\tt{More \: to \: know: \: }}\mid}} \:$

$\bf{\dag}\:\:\underline{\textsf{Fraction Rules :}}\\\\\bigstar\:\:\sf\dfrac{A}{C} + \dfrac{B}{C} = \dfrac{A+B}{C} \\\\\bigstar\:\:\sf{\dfrac{A}{C} - \dfrac{B}{C} = \dfrac{A-B}{C}}\\\\\bigstar\:\:\sf\dfrac{A}{B} \times \dfrac{C}{D} = \dfrac{AC}{BD}\\\\\bigstar\:\:\sf\dfrac{A}{B} + \dfrac{C}{D} = \dfrac{AD}{BD} + \dfrac{BC}{BD} = \dfrac{AD+BC}{BD} \\\\\bigstar\:\:\sf\dfrac{A}{B} - \dfrac{C}{D} = \dfrac{AD}{BD} - \dfrac{BC}{BD} = \dfrac{AD-BC}{BD}\\\\\bigstar \:\:\sf \dfrac{A}{B} \div \dfrac{C}{D} = \dfrac{A}{B} \times \dfrac{D}{C} = \dfrac{AD}{BC}$