Question

the sum of two resistors is 6 ohms and their equivalent resistance when connected in parallel is 1.5 ohms the product of two resistances​

Answer 1

R1 +R2 =6

R1 XR2 /R1 + R2 = 1.5


R1 X R2 =(R1 + R2) X1. 5

= 6 X 1.5

= 9

Answer 2

Answer:

The product of both the resistances is 9.

Explanation:

Given that,

The sum of two resistances is 6 ohms and their equivalent resistance when connected in parallel is 1.5 ohms.We are required to find the product of both the resistances.

Let the resistances be $R_{1}$ and $R_{2}$.According to the given data we have,

$R_{1}+R_{2}=6\Omega--- > (1)$

The equivalent resistance when connected in parallel is given by the relation

$R_{eq}=\frac{R_{1}R_{2}}{R_{1}+R_{2}}$

Equating the equivalent resistance and substituting equation 1 in above relation,we get

$1.5=\frac{R_{1}R_{2}}{6}= > R_{1}R_{2}=1.5\times6=9$

Therefore,The product of both the resistances is found to be 9.

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