The sum of two roots of the equation x² - 64 = 0 is
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Answer:
x2−64=0 x2−64=0
Rewrite
64 64 as
82 82 .
x2−82=0 x2−82=0
Since both terms are perfect squares, factor using the difference of squares formula,
a2−b2=(a+b)(a−b) a2−b2=(a+b)(a−b) where
a=x a=x and
b=8 b=8 .
(x+8)(x−8)=0 (x+8)(x−8)=0
Step-by-step explanation:
x2−64=0 x2−64=0
Rewrite
64 64 as
82 82 .
x2−82=0 x2−82=0
Since both terms are perfect squares, factor using the difference of squares formula,
a2−b2=(a+b)(a−b) a2−b2=(a+b)(a−b) where
a=x a=x and
b=8 b=8 .
(x+8)(x−8)=0 (x+8)(x−8)=0
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