Question

the sum of two rotaitional number is -1 upon 6 if one of them is -4 find other​

Answer 1

Step-by-step explanation:

$let \: the \: second \: no \: = p \\ according \: to \: question \\ \frac{ - 1}{6} + p = - 4 \\ \frac{ - 1 + 6p}{6} = - 4 \\ - 1 + 6p = - 24 \\ 6p = 25 \\ p = \frac{25}{6}$

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