Question

the sum of two two integer is 99.if one number is 20%more than the other ,find the two numbers​

Answer 1

Step-by-step explanation:

Given:-

The sum of two integers is 99. If one number is

20% more than the other number .

To find:-

The sum of two integers is 99. If one number is

20% more than the other number .Find the other

number?

Solution:-

Let the other number be X

Then the one of the numbers = 20% more than

the other number

=>One of the number = X + 20% of X

=>X + (20X/100)

=>X+(X/5)

=>(5X+X)/5

=>6X/5

The one number is 6X/5

The sum of the two numbers

=> One number + Other number

=>(6X/5)+X

=>(6X+5X)/5

=>11X/5

According to the given problem

The sum of two numbers = 99

=>11X/5 = 99

=>11X = 99×5

=>X = 99×5/11

=>X = 9×5

=>X = 45

The value of other number = 45

Then the one number = 99-45 = 54

Answer:-

The two numbers for the given problem are

54 and 45

Check:-

One number = 20% more than other number

=>45+(20%of45)

=>45+(20×45/100)

=>45+(45/5)

=>45+9

=>54

Verified the given relations