the sum of two two integer is 99.if one number is 20%more than the other ,find the two numbers
Answers
Step-by-step explanation:
Given:-
The sum of two integers is 99. If one number is
20% more than the other number .
To find:-
The sum of two integers is 99. If one number is
20% more than the other number .Find the other
number?
Solution:-
Let the other number be X
Then the one of the numbers = 20% more than
the other number
=>One of the number = X + 20% of X
=>X + (20X/100)
=>X+(X/5)
=>(5X+X)/5
=>6X/5
The one number is 6X/5
The sum of the two numbers
=> One number + Other number
=>(6X/5)+X
=>(6X+5X)/5
=>11X/5
According to the given problem
The sum of two numbers = 99
=>11X/5 = 99
=>11X = 99×5
=>X = 99×5/11
=>X = 9×5
=>X = 45
The value of other number = 45
Then the one number = 99-45 = 54
Answer:-
The two numbers for the given problem are
54 and 45
Check:-
One number = 20% more than other number
=>45+(20%of45)
=>45+(20×45/100)
=>45+(45/5)
=>45+9
=>54
Verified the given relations