Question

The sum of two unit vectors is a unit vector the difference of two unit vector is of magnitude

Answer 1

Answer:

${1 }^{2} + {1}^{2} + \cos( \alpha ) = 1$

$\alpha = 120 \: \: \because \: \cos( \alpha ) = \frac{ - 1}{2}$

now

$|a - b | = \sqrt{} ({1}^{2} + {1}^{2} - 1 \times \frac{ - 1}{2} )$

$= \sqrt{3}$

Answer 2

Answer:

Explanation:let a and b be the unit vectors

√(1^2+1^2+2cos∅)=1

1^2+1^2+2cos∅=1

2+2cos∅=1

2cos∅=-1

cos∅=-1/2

a-b= √1^2+1^2-2cos∅

    =√2-2*(-1/2)

    =√2-(-1)

   =√3