The sum of two unit vectors is also a vector of unit magnitude, then the magnitude of the
difference of the two unit vectors
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Answer:
Explanation:
Solution,
Let us assume a and b be the two vectors,
Resultant of sum, R = √a² + b² + 2ab cosΘ
We know that,
a = b = 1
It's a unit vector.
= 1 + 1 + cosΘ
cosΘ = - 1/2
Here we will get,
Difference of resultant = Magnitude (a - b)
R = √a² + b² + 2ab cosΘ
We have,
a = b = 1 and,
cosΘ = - 1/2
R = √1 + 1 + 1
R = √3
Hence, the magnitude of the difference of the two-unit vectors are √3.
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