Question

the sum of twonumbers is 110.one-fifth of the larger number is 8more than one-ninths ofsmaller number. find the numbers​

Answer 1

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Answer:

according to the question,

1/5*x = 1/9*x+9

then,

1/5*x + 1/9*x+9 = 110

x/5 + x/9 = 110-9 = 101

(45x + 45x) / 45 = 101 (by LCM)

90x/45 = 101

2x = 101

x = 101/2 = 50.5

the the two values will be

1/5*50.5 = 10.1

1/9*50.5+9 = 5.611 (approximately)

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