The sum of five consecutive numbers is 270. What is the sum-of the second and the fifih number ?
(1) 108
(2) 107
(3) 110
(4) Cannot be determined
(5) None of these
Answers
Answered by
1
let the a number = x
(x) + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 270
Simplify.
5x + 10 = 270
Isolate the x. Note the equal sign. What you do to one side you do to the other. Also do opposite of PEMDAS.
First subtract 10 from both sides
5x + 10 (-10) = 270 (-10)
5x = 270 - 10
5x = 260
Next, divide 5 from both sides
5x/5 = 260/5
x = 260/5
x = 52.
Now you are trying to find the sum of the second (x + 1), and the fifth number (x + 4)
Plug in 52 for x
(52 + 1) + ( 52 + 4) = (53) + (56) = 109
(5) None of these is your answer, because the answer is 109
hope this helps
Answered by
1
Hey user
Here is your answer :-
Let the smallest number be " x "
So other numbers are x + 1 , x + 2 , x + 3 & x + 4
So
x + 1 + x + x + 2 + x + 3 + x + 4 = 270
=> 5x + 10 = 270
=> 5x = 260
=> x = 52
So the numbers are 52 , 53 , 54 , 55 & 56
Here is your answer :-
Let the smallest number be " x "
So other numbers are x + 1 , x + 2 , x + 3 & x + 4
So
x + 1 + x + x + 2 + x + 3 + x + 4 = 270
=> 5x + 10 = 270
=> 5x = 260
=> x = 52
So the numbers are 52 , 53 , 54 , 55 & 56
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