Question

the sum of which consecutive numbers is 398​

Answer 1

Answer:

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Answer 2

Let the numbers be ⇒ $x$ , $x+1$ , $x+2$ and $x+3$

Sum of consecutive numbers = 398

$x+x+1+x+2+x+3=398$

$4x+6=398$

$4x = 398-6$

$4x = 392$

$x = \frac{392}{4}$

$x = 98$

∴ The consecutive numbers are -

$x = 98$

$x+1 = 98+1 = 99$

$x+2=98+2=100$

$x+3 = 98+3 = 101$

∴ The four consecutive numbers were 98, 99, 100 and 101.

∴ The sum of 98, 99, 100 and 101 is equal to 398.