Question

the sum of which four consecutive numbers is 398​

Answer 1

Answer:

$\red { Required \: four \: numbers \:are,}$

$\green {98,99,100 \:and \:101}$

Step-by-step explanation:

Let x ,(x+1),(x+2) and (x+3) are four consecutive numbers.

$Sum \:of \: four \: numbers = 398\:(given)$

$\implies x+x+1+x+2+x+3 = 398$

$\implies 4x + 6 = 398$

$\implies 4x = 398 - 6$

$\implies 4x = 392$

$\implies x = \frac{392}{4}$

$\implies x = 98$

Therefore.,

$\red { Required \: four \: numbers \:are,}$

$x = 98,\\x+1 = 98+1= 99,\\x+2 = 98+2 = 100,\\and \: x+3 = 98+3 = 101$

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Answer 2

Answer:

Step-by-step explanation: