The sum of x coordinate of the intersection of x 2 +y 2 =36 and x 2 -y 2 =6,is
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The given equations are,
x²+y²=36 -----------(1)
x²-y²=6 --------------(2)
Adding (1) and (2) we get,
2x²=42
or, x=⁺₋√21
∴, The sum of the x-coordinates is:
√21+(-√21)=0
x²+y²=36 -----------(1)
x²-y²=6 --------------(2)
Adding (1) and (2) we get,
2x²=42
or, x=⁺₋√21
∴, The sum of the x-coordinates is:
√21+(-√21)=0
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