the sum of x term of an AP n2+3n find its 20th term
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Here S
n
=3n+n
2
Now, first term a=S
1
⇒a=3×1+1
2
=4 and
Sum of first two terms=a
1
+a
2
=a+(a+d)=S
2
=3×2+2
2
=10
⇒2a+d=10⇒8+d=10⇒d=2
Now, a
2
=a+d⇒a
2
=4+2=6
a
3
=a+2d⇒a
3
=4+2×2=8
a
15
=a+14d⇒a
15
=4+14×2=32
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Answer:
let suppose x
2+3 n2
20th
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