Question

The sum of xy+z and x+y is​

Answer 1

Answer:

All possible numbers formed by the digits x,y and z are : xyz,yxz and zxy.

∴xyz+yxz+zxy=(100x+10y+z)+(100y+10z+x)+(100z+10x+y)

=100x+10x+x+10y+100y+y+z+100z+10z

=111x+111y+111z

=111(x+y+z)

=3×37(x+y+z)

Therefore, xyz+yzx+zxy is divisible by 37.

Hence, option (C) is correct.