the sum of zeroes of 5-6x+3² is
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Answered by
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the give polynomial has only one zero it cannot be expressed in sum of its two zero
please check the question
Answered by
1
Answer:
6
Step-by-step explanation:
I assume the expression is
x² - 6x + 5 = (x - 1)(x - 5)
zeros are 1 and 5
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