Question

The sum of zeroes of a guadratic polynomial
kx 2-3x+1is1, find the value of k.​

Answer 1

Step-by-step explanation:

kx²-3x+1

$\frac{ - b - \sqrt{b ^{2} - 4ac } }{2a}$

here a=k,b=3,c=1

$\frac{ - 3 - \sqrt{3 ^{2} - 4k(1) } }{2(k)} = 1$

$- 3 - \sqrt{ {3}^{2} - 4k } = 2k$

$- \sqrt{ {3}^{2} - 4k } = 2k - 3$

squaring on both sides

${( - \sqrt{ {3}^{2} - 4k } } \: )^{2} = {(2k - 3)}^{2}$