The sum of zeroes of a quadratic polynomial 3x²+2kx+x-k-5 is half of their product. Find the value of k
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As per question-
-b/a=1/2*c/a
-2k-1/3=1/2*-k-5/3
-2k-1=-k-5/2
-4k-2=k-5
-5k=-3
k=3/5
-b/a=1/2*c/a
-2k-1/3=1/2*-k-5/3
-2k-1=-k-5/2
-4k-2=k-5
-5k=-3
k=3/5
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