Question

the sum of zeroes of a quadratic polynomial 6x²-7x-3​

Answer 1

Answer:

Let 6x2 - 7x-3 be p(x) =0

so,6x2 - 7x-3 =0

6x2 - (9-2) x -3

6x2 - 9x + 2x -3

(6x2 - 9x)(2x-3)

3x(2x-3) +1 (2x-3)

(3x +1) (2x -3) = 0

⇒ 3x +1 = 0

⇒ 2x -3 = 0

⇒ x =3/2

⇒ x = - 1/3

sum of zeroes = -1/3 + 3/2 =7/6 = -b/a

product of zeroes =- 1/3 * 3/2 = - 3/6 or -1/2 = c/a

Step-by-step explanation:

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