The sum of zeroes of a quadratic polynomial Kx2–3x +l is 1, find the
value of K.
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Step-by-step explanation:
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Solution:
Let p(x) = kx² - 3x + 1
Here,
- a (coefficient of x²) = k
- b (coefficient of x) = -3
- c (constant term) = 1
So,
→ Sum of zeroes = -b/a = -(-3)/k = 3/k
It's given that,
→ Sum of zeroes = 1
So, according to the given condition,
→ 3/k = 1
→ k = 3/1
→ k = 3
★ So, the value of k is 3
Answer:
- k = 3
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