Question

The sum of zeroes of polynomial 6x2 + 13x + 7​

Answer 1

Answer:

-13/6

Step-by-step explanation:-

6x² + 13x + 7​ = 0

⇒ 6x² + 6x + 7x + 7 = 0

⇒​(6x² + 6x) + (7x + 7) =0

⇒6x(x + 1) + 7(x+1) = 0

⇒(x + 1)(6x + 7) = 0

⇒ x = -1 or x = -7/6

Now

Sum of zeroes = (-1) + (-7/6)

                         

                        = -1 -7/6

                       

                        = -13/6

Answer⇒ -13/6

More things to know:-

• (a + b)² = a² + 2ab + b²

• (a - b)² = a² - 2ab + b²

• a² - b² = (a + b)(a - b)

• (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2 ca

                        = a² + b² + c² + 2(ab + bc + ca)  

• (a + b)³ = a³ + b³ + 3ab(a + b)

                    =  a³ + b³ + 3a²b + 3ab²  

• (a - b)³ = a³ - b³ - 3ab(a - b)                    

                   = a³ - b³ - 3a²b + 3ab²    

• a³ + b³ = (a + b)(a² - ab + b²)

• a³ - b³ = (a - b)(a² + ab + b²)

• a³+b³ +c³- 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)

• (x + p)(x + q) = x² + (p + q)x + pq

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