Question

the sum of zeroes of polynomial 9x^2-6x+1​

Answer 1

p(x) = 9x² - 6x + 1

On comparing,

a = 9, b = -6 , c = 1

Sum of zeroes = -b/a

==> -(-6) / 9

==> 6/9

==> 2/3

Answer 2

Answer:

the sum of the zeros are (-b/a)

here , a=9b=-6c=1

therefore, -(-6)/9

6/9

2/3 is the answer

Step-by-step explanation:

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