Question

the sum of zeroes of quadratic polynomial is 15/4 and the product is 3 . Find polynomial​

Answer 1

Answer:

ATQ

$\alpha + \beta = \frac{15}{4}$

$\alpha \beta = 3$

We know that the polynomial is of the form

$P(x) = x^{2} - (\alpha + \beta)x + \alpha \beta$

$P(x) = x^{2} - (\frac{15}{4} )x + 3$

$P(x) = x^{2} - \frac{15x}{4} + 3$

$P(x) = \frac{4x^{2} - 15x + 12}{4}$

As we know that P(x) is always equal to 0

Therefore

$0 = \frac{4x^{2} - 15x + 12}{4}$

$0 = 4x^{2} - 15x + 12$

Therefore the polynomial is $P(x) = 4x^{2} - 15x + 12$

Answer 2

4x square - 15x + 12

Step-by-step explanation:

easy answer by diksha