the sum of zeroes of the polynomial f(x) = 2x3 - 3kx2 + 4x - 5 is 2, then k =
Answers
Answer:
Answer:k=4
Step-by-step explanation:
Sum of zeroes=-b/a
So 6=-(-3k)/2
6=3k/2
k=6×2/3=12/3=4
So k=4
Step-by-step explanation:
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Given :
Sum of the zeroes of the polynomial f(x) = 2x³– 3kx² + 4x – 5 is 6.
To find :
Value of k .
Concept :
For a cubic polynomial is in the form of ax³ + bx² + cx + d :
∵ Sum of zeros = -b/a where, b is coefficient of x² and a is the coefficient of x³
Solution :
Now , f(x) = 2x³ - 3kx² + 4x - 5
Or, f(x) = 2x³ + (-3kx²) + 4x + (-5)
Now according to concept :
⇒ -coefficient of x²/coefficient of x³ = 6
⇒ -(-3k)/2 = 6
⇒ 3k/2 = 6
⇒ 3k = 6 × 2
⇒ 3k = 12
⇒ k = 12/3
⇒ k = 4
∴ Required value of k = 4
Given :
Sum of the zeroes of the polynomial f(x) = 2x³– 3kx² + 4x – 5 is 6.
To find :
Value of k .
Concept :
For a cubic polynomial is in the form of ax³ + bx² + cx + d :
∵ Sum of zeros = -b/a where, b is coefficient of x² and a is the coefficient of x³
Solution :
Now , f(x) = 2x³ - 3kx² + 4x - 5
Or, f(x) = 2x³ + (-3kx²) + 4x + (-5)
Now according to concept :
⇒ -coefficient of x²/coefficient of x³ = 6
⇒ -(-3k)/2 = 6
⇒ 3k/2 = 6
⇒ 3k = 6 × 2
⇒ 3k = 12
⇒ k = 12/3
⇒ k = 4
∴ Required value of k = 4