Question

the sum of zeros = alfa + beeta = -8 and products of zeros = alfa.beeta = 6 . now find a polynomial whose zeros are 1/alfa and 1/beeta
A) 6x^2 + 8x + 1
B) 6x^2 - 8x - 1
C) 6x^2 - 4x + 6
D) 6x^2 - 8x + 1​

Answer 1

Answer:

option (a)

Step-by-step explanation:

given

alpha+beta= -8

alpha.beta= 6

then

1/alpha×1/beta=1/6

and 1/alpha +1/beta=(beta+alpha)/alpha.beta

= -8/6

therefore the equation is

x²-(-8/6)x+1/6

x²+8/6x+1/6

6x²+8x+1

so answer is option (a)