Question

The sum of zeros is 2 and the product of zeros is -3 then p of X is_____.

Answer 1

Answer: mrk as brainlist pls....

Step-by-step explanation:

x^2 - Sx + P

( S = 2 )

( P = -3 )

x^2 -2x -3

Answer 2

Given :

• Sum of zeroes = 2
• Product of zeroes = - 3

To Find :

• Value of p ( x )

Solution :

$\large \tt p(x) = {x}^{2} -( \alpha)x + \beta \\ \\ \tt p(x) = {x}^{2} - (2)x + ( - 3) \\ \\ \boxed{ \tt p(x) = {x}^{2} - 2x - 3}$

Verification :

$\large \tt Sum \: of \:zeroes = \frac{ - b}{a} \\ \\ \tt \implies \frac{ - ( - 2)}{1} \\ \\ \tt \implies2 \\ \\ \tt\large product \: of \:zeroes = \frac{ c}{a} \\ \\ \tt \implies \frac{ - 3}{1} \\ \\\tt \implies - 3$