Question

the sum of zeros of 8 x square minus kx + 1 is equal to -1 then what is K in
please ans fast ​

Answer 1

Given :-

• Sum of zeros of Polynomial 8x² - kx + 1 is (-1) .

To Find :-

• Value of k ?

Concept used :-

→ The sum of the roots of the Equation ax² + bx + c = 0 , is given by = (-b/a)

and ,

→ Product of roots of the Equation is given by = c/a.

Solution :-

Comparing we get :-

→ a = 8

→ b = (-k)

→ c = 1

So,

→ sum of zeros = (-b/a) = -(-k)/8 = (k/8)

Now, given that, sum is (-1) .

So,

→ (k/8) = (-1)

→ k = (-8) (Ans).

Hence, value of k will be (-8).

Answer 2

Answer:

k= -8

Step-by-step explanation:

The provided pic is the correct explanation.