the sum ofmagnitudes of two forces acting at a point 16N .the resultant of these forces is perpendicular to smaller force and has a magnitude.of8N. If the smaller force is of magnitude x,then the value ofx,is
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11th
Physics
Work, Energy and Power
Scalar Product
The sum of magnitudes of tw...
PHYSICS
The sum of magnitudes of two forces acting at a point is 16N. If the resultant force is 8N and its direction is perpendicular to smaller force, then the forces are:
December 26, 2019
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Rajender Advani
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ANSWER
The correct answer is A.
Given,
The magnitude of two n forces is 16N
The resultant force is 8N
so,
X+Y16(X<Y) and R is the resultant force perpendicular to X.
According to the Pythagoras theorem,
⇒R
2
=Y
2
−X
2
=(Y−X)(Y+X)=16(Y−X)
⇒(Y−X)=
(Y+X)
R
2
=
16
8
2
⇒
16
64
=4
(Y+X)=16 and (Y−X)=4
By solving a linear equation in two variable we get,
Y=10N and X=6N
solution
December 26, 2019
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