the sum og digits of 2 digit no. is 12 . The number obtain by reversing the order of digit of yhe given no. exceeds the given no. by 18 .Find the 2 digit no.
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☆Hello friend☆
Let's original number be 10x+ y
10y+ x + 18 = 10x+ y
18 = 10x - x + y - 10y
18 = 9x-9y
Each getting 2 ,
x - y = 2 ---------(1)
x + y = 12 ---------(2)
Adding both equations
2x = 14
x = 14/2 = 7
y = 12-7 = 5
So original number is 10 × 7 +5 =75
Hope it helps☺!
Let's original number be 10x+ y
10y+ x + 18 = 10x+ y
18 = 10x - x + y - 10y
18 = 9x-9y
Each getting 2 ,
x - y = 2 ---------(1)
x + y = 12 ---------(2)
Adding both equations
2x = 14
x = 14/2 = 7
y = 12-7 = 5
So original number is 10 × 7 +5 =75
Hope it helps☺!
ShuchiRecites:
no u have not given steps
and i do not wabt t talk here more
whose ever ans will be wrong will be deleted
Not interested if u cannot get such an easy thing
ok i see i did a silly mistake, but ur answer was reported bcz u have not given steps
NYC soluation
sorry for unconvinience bu i think both answers will be deleted
bcz mine answer is wrong , ur answe is correct but u have not given solution
I have given solution
frnd u have given equation and saod solve it u will get 57
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