The sum oif the digit of a two digit number is 12. if the digit are reversed, the new number become 4/7 times the original number . Find the original number
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let unit digit be x
tenth digit is 12-x
original number =10(12-x)+x=120-10x+x=120-9x
reverse number =10x+12-x=9x+12
A/Q
9x+12=4/7(120-9x)
7(9x+12)=4(120-9x)
63x+84=480-36x
63x+36x=480+84
99x=564
x=564/99
tenth digit is 12-x
original number =10(12-x)+x=120-10x+x=120-9x
reverse number =10x+12-x=9x+12
A/Q
9x+12=4/7(120-9x)
7(9x+12)=4(120-9x)
63x+84=480-36x
63x+36x=480+84
99x=564
x=564/99
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