The sum pf the 4th and 8th term of an A.P. is 24 and the sum of the 6th and 10th term is 44. Find the first three term of A.P.
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a4+a8=24
a6+a10=44
a+3d+a+7d=24
a+5d+a+9d=44
2a+10d=24 (1)
2a+14d=44 (2)
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4d=20
d=5
put d in equation (1)
2a+10d=24
2a+10(5)=24
2a=24-50
a=-26/2
a=-13
A2=a+d
A2=-13+5=-8
A3=a+2d
a3=-13+2(5)
A3=-13+10
=-3
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