the sum required to earn a monthly interest of 1200ruppes at 18% p.a SI is
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Answered by
0
I=₹1200
R=18%
T=
12
1
year
I=
100
P×R×T
1200=
100×12
P×18×1
P=
18
120000×12
=₹80000
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Answered by
1
Answer:
80,000
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