The sum S of the first n natural numbers is given by the relation s=n(n+1)/2find n if the sum is 120
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Answer:15
Step-by-step explanation:S=n(n+1)/2
If S=120
Then,n(n+1)/2=120
n^2+n=240
n^2+n-240=0
Comparing with ax^2+bx+c=0
a=1
b=1
c=-240
D =b^2-4ac
D=1+4*240
D=961
√D=31
n =-b+-√D/2a
n= -1+-31/2
n=-16 or. 15
n can't be negative
So n=15
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