Question

The sum (S) of the squares of the first n natural numbers is equal to the sum of the first 2n natural numbers. What is the remainder when S is divided by 2n? ​

Answer 1

Answer:

(n+1)/6

Step-by-step explanation:

S= [n (n+1)(2n+1)]/6

and sum of first 2n numbers= [2n(2n+1)]/2= n(2n+1)

now S/ n(2n+1)= (n+1)/6