Question

the sum the age's of A and B is 46 . five years ago the age of B was twice that of A .find A's age.​

Answer 1

Answer:

Step-by-step explanation:

Let A 's age = x

And B 's age =y

5 year ago , A 's age = x -5

B ' s age = y- 5

A to q

x + y = 46..........(1)

2nd condition ( y- 5) = 2 (x -5)

y- 5 = 2x -10

y = 2x -5...........(2)

By (1) put the value of y in (1)

x + 2x -5 =46

3x = 46 +5 = 51

X = 51/3 = 17

So A 's age = 17 year

Answer 2

simple and easy soln

hope it will help you.........

Brainlist answer