the sum the sum of the digits of a two-digit number is 10 the number formed by reversing the digitis 18 less than the original number find the original number
Answers
Answered by
60
Step-by-step explanation:
Let the no be 10x+y
Reversed no is 10y+x
10x+y-18=10y+x
= 9x-9y=18
=x-y=2
Given x+y=10
On solving we get x=6
y=4
Req no = 64
Hope it helps ✌️✌️✌️
Answered by
75
Answer:
The Original Number is 64.
Step-by-step explanation:
Given :
Sum of digits = 10
Number formed after reversing the digits = 18 less than than the Original Number.
To find :
The original number
Solution :
Let the -
- Units place be x
- Tens place be y
✯
The sum of the digits of a two digit number is 10.
The number formed by reversing the digits is 18 less than the original number.
Substitute the value of y in equation (1)
✯
Original number = 64
The Original Number is 64.
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