the sum three consecutive numbers are138 . find the number
Answers
Answered by
2
let the consecutive number be
x
x+1
x+2
so
x+x+1+x+2+x+3 = 138
3x+6 = 138
3x = 138-6
3x = 132
x = 132/3
x = 44
then
x+1 = 44 +1
= 45
x+2 = 44+2
= 46
x+3 = 44+3
= 47
x
x+1
x+2
so
x+x+1+x+2+x+3 = 138
3x+6 = 138
3x = 138-6
3x = 132
x = 132/3
x = 44
then
x+1 = 44 +1
= 45
x+2 = 44+2
= 46
x+3 = 44+3
= 47
pranshu81:
anything else
Answered by
2
First consecutive number = x
Second consecutive number = x + 1
Third consecutive number = x + 2
Total sum = 138
So; x + (x + 1) + (x + 2) = 138
x + x + x + 1 + 2 = 138
3x + 3 = 138
3x = 138 - 3
3x = 135
x = 135 / 3
x = 45
So first consecutive number = 45
second consecutive number = 46
third consecutive number = 47
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Second consecutive number = x + 1
Third consecutive number = x + 2
Total sum = 138
So; x + (x + 1) + (x + 2) = 138
x + x + x + 1 + 2 = 138
3x + 3 = 138
3x = 138 - 3
3x = 135
x = 135 / 3
x = 45
So first consecutive number = 45
second consecutive number = 46
third consecutive number = 47
HOPE THAT HELPED YOU. MARK AS BRAINLIEST
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