The sum to 2 numbers is 12 and the diffrence is 4
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Answered by
1
Answer:
Let the 2 numbers be x and y with x > y
#rArrxcolor(red)(+y)=12to(1)larr"sum of 2 numbers"#
#rArrxcolor(red)(-y)=4to(2)larr" difference of numbers"#
Adding the 2 equations, term by term on both sides, will eliminate y leaving an equation in x that we can solve.
#rArr(1)+(2)" gives"#
#(x+x)+(color(red)(-y+y))=(4+12)#
#rArr2x=16#
divide both sides by 2
#(cancel(2) x)/cancel(2)=16/2#
#rArrx=8#
Substitute this value into equation ( 1 ) and solve for y
#rArr8+y=12#
#rArry=12-8=4#
#"Thus the 2 numbers are " 8" and " 4#
Answered by
1
Answer:
8+4=12
Step-by-step explanation:
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