the sum to n terms of an ap is n(n+3) the common difference
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Answer:
Sum of AP=n/2*(2a+(n-1)d)
Step-by-step explanation:
The above is equal to n(n+3) hence equating both we have
n(n+3)=n/2 (2a+(n-1)d)
2n+6=2a+(n-1)d
2n+6=2a+dn-d
Comparing the equations we have d=2
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